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Craps StrategyThe Can't Lose On Any Number System
This system involves betting against the shooter, and then hedging whatever point comes up so that you win if the point is hit....or the player sevens out! This is how the system works:
First you bet a $30 Don't Pass bet along with a $1 Pass bet. If a point is made, you now place one of the following bets (depending on what point was placed) If the point is a 4 or 10, you will place a $20 Free Odds bet behind your $1 Pass bet. If the point is a 5 or 9, you will place a $24 Free Odds bet behind your $1 Pass bet. If the point is 6 or 8, you will place a $27 Free Odds bet behind your $1 Pass bet.
From this point on, you have no chance of losing.
Now lets look at this system mathematically to show you how it works: On the come out roll.....If you roll a 2 or 3, you win $29 You lose $29 on a seven or eleven. If you throw a 12, you lose
$1 From
this point on....you can't lose Now if the point is 4 or 10, you win $11 if you throw another 4 or 10, or $9 if you throw a seven! If the point is 5 or 9, you win $7 if you throw another 5 or 9, or $5 if you throw a seven! If the point is 6 or 8, you win $1 if you throw another 6 or 8, and $2 if you throw a seven!
So you can see that by playing this system, there is no possible way to lose after the come out roll. There are some neat things that we can do to hedge this bet even more, and will allow us to lose even less of the time. I will post this "enhanced" version of the system next time, after you have time to evaluate this one.
As always, good luck,
Brian Fischer
